After the week of the 30th of June, Jack Draper has recorded the best percentage in terms of % tiebreaks won in after conquering 4 out of 4 in the TOP10.
Here is the full list of the top10.
Rank | Player | Tiebreak per |
---|---|---|
1 | Jannik Sinner | 72.7% |
5 | Jack Draper | 72.7% |
8 | Alex de Minaur | 69.2% |
3 | Alexander Zverev | 62.9% |
2 | Carlos Alcaraz | 61.9% |
6 | Ben Shelton | 57.5% |
9 | Holger Rune | 57.1% |
10 | Lorenzo Musetti | 56.3% |
4 | Taylor Fritz | 44.1% |
7 | Novak Djokovic | 41.2% |
Jack Draper in 2025
Now the world no.4 (career-high), Draper played his last match on the 21st of June when he was overcome by world no.25 Jiri Lehecka 6-4 4-6 7-5 in the semifinal in London (draw).
At present, during this year Jack owns a composed 28-8 match record. This year, the Brit clinched 1 title in Indian Wells. The Brit was the finalist in Doha and Madrid.
Jack Draper will play the world no.38 Sebastian Baez in the 1st round. Their current head to head is 2-0 for Draper.
Draper clinched 1 title in 2025 in Indian Wells. Jack got to the final in Doha (Qatar ExxonMobil Open) and in Madrid (Mutua Madrid Open).