Christopher O Connell and Beibit Zhukayev will play each other in the 2nd round of the Kobe Challenger for the 1st time in their career. They are scheduled to play on Thursday at 1:30 pm on COURT B. Here the head to head stats and relative prediction.
Prediction, odds and live streaming
The pick for Tennis Tonic is Christopher O Connell who should win in 2 sets.
As per the initial odds, Christopher O Connell is the pick to win this match.
Christopher O Connell -> 1.25
Beibit Zhukayev -> 3.78
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Prediction and head to head Christopher O Connell vs. Beibit Zhukayev
There is no head to head record between Christopher O Connell and Beibit Zhukayev since this will be the first time that they will square off in the main tour.
Christopher O Connell
| Year | Total | Hard | Clay | I.hard | Grass | Carpet |
|---|---|---|---|---|---|---|
| 2024 | 11-13 | 9-8 | 2-4 | 0-0 | 0-1 | 0-0 |
| 2023 | 38-34 | 19-18 | 11-9 | 4-3 | 4-4 | 0-0 |
| 2022 | 50-25 | 30-16 | 12-5 | 3-1 | 5-3 | 0-0 |
| 2021 | 22-16 | 14-9 | 3-3 | 1-1 | 4-3 | 0-0 |
| 2020 | 12-12 | 4-5 | 4-3 | 4-4 | 0-0 | 0-0 |
Ranked no. 84 (career-high), the Australian got to the 2nd round after beating Colin Sinclair 6-77 7-610 7-63.
In the 1st round against Sinclair, O Connell recovered from a 1-set down deficit before winning (6-77 7-610 7-63). During the match, O Connell and Sinclair scored the same amount of points (129). However, the world no. 84 was stronger during the important points and that was the most significant difference in the match. The Australian was exceptionally aggressive to blast 57 winners.
Regarding the service games, O Connell struck 12 aces and he committed only 4 double faults. Overall, Christopher O Connell was extremely effective on serve to win 74% (57/77) of his 1st serve and 61% (34/56) on the second serve. However, this didn’t prevent his to concede the serve once. Christopher broke Sinclair once after converting 25% of his break points (1/4).
O Connell has a solid win-loss record in the last 10 years having won 64% of his matches (318-177). 1-0 on indoor hard courts in 2022. In connection with his performance on the same surface of this competition, O Connell has an overall 13-8 record in the last years on indoor hard courts.
Christopher’s best result of the season was getting to the final in the Split Challenger,the Porto Challenger and the Yokohama Challenger.
Christopher has an overall 48-24 win-loss record in 2022, 1-0 on indoor hard courts (See FULL STATS).
Previously in the Kobe Challenger
The Australian has never competed in this tournament before.
Beibit Zhukayev
| Year | Total | Hard | Clay | I.hard | Grass | Carpet |
|---|---|---|---|---|---|---|
| 2024 | 18-17 | 6-8 | 6-4 | 0-1 | 6-4 | 0-0 |
| 2023 | 37-30 | 19-16 | 1-3 | 11-8 | 2-2 | 4-1 |
| 2022 | 43-30 | 33-21 | 1-2 | 9-7 | 0-0 | 0-0 |
| 2021 | 19-21 | 13-10 | 4-9 | 2-2 | 0-0 | 0-0 |
| 2020 | 0-0 | 0-0 | 0-0 | 0-0 | 0-0 | 0-0 |
Ranked no. 326, Zhukayev got to the 2nd round after beating Yuichi Sugita 4-6 6-4 6-4.
In the 1st round against Sugita, Beibit recovered from a 1-set down deficit before winning (4-6 6-4 6-4). During the match Zhukayev scored 96 points vs Sugita’s 87. The Kazakhstani was extremely aggressive to blast 50 winners.
About the serving games, Zhukayev buried his opponent with 24 aces and he committed only 3 double faults. Beibit Zhukayev lost the serve twice and he saved 7 break points. Furthermore, Zhukayev put 67% of his first serves in, winning 76% (50/66) of the points behind his 1st serve and 45% (15/33) on the 2nd serve. The Kazakhstani broke Sugita 3 times after converting 50% of his break points (3/6).
Zhukayev’s best result of the season was reaching the final in Sultan.
The Kazakhstani has a compiled 42-28 win-loss record in 2022, 9-6 on indoor hard courts (See FULL STATS).
H2H Performance in the tournament
Matches, sets, games and points
| Points | O Connell | Zhukayev |
|---|---|---|
| Match played | 1 | 1 |
| Tot Set | 3 | 3 |
| Tot Games | 39 | 30 |
| Pts | 129-129 | 96-87 |
| Total Points | 258 | 183 |
| Winners | 57 | 50 |
| %Winners | 44% | 52% |
Both O Connell and Zhukayev played 1 match. Both players lost a set in the event. Christopher O Connell surrendered 1 set, while Beibit Zhukayev lost 1 set. Talking about their workload, O Connell and Zhukayev have played the same amount of sets 3. However, O Connell played 9 games more than Zhukayev. O Connell scored 57 winners (44% of the total points). On the other side, The Kazakhstani managed to score 50 winners (52%).
Serve Performance
| Serve | O Connell | Zhukayev |
|---|---|---|
| Aces | 12 | 24 |
| Avg per match | 12 | 24 |
| 1st in | 77/133 | 66/99 |
| %1st in | 58% | 67% |
| 1st pts | 57/77 | 50/66 |
| %1st pts | 74% | 76% |
| 2nd pts | 34/56 | 15/33 |
| %2nd pts | 61% | 45% |
O Connell fired 12 aces . Zhukayev struck 24 aces . O Connell won 74% points behind his first serve. He had a solid display on his second serve to win 61% of the points. On the other side, Zhukayev won 76% of the points on his first serve. He had a solid display on his second serve to win 45% of the points.
How they played the important points
| Breaks | O Connell | Zhukayev |
|---|---|---|
| Won | 1 | 3 |
| Converted | 1/4 | 3/6 |
| % Converted | 25% | 50% |
| Conceded | 5 | 9 |
| Saved | 4 | 7 |
| % Saved | 80% | 78% |
| Times Broken | 1 | 2 |
Christopher broke his opponent once with a 25% conversion rate. The Australian conceded his serve once and he saved 80% of the break points that he conceded. Beibit broke his opponent 3 times with a 50% conversion rate. Beibit conceded his serve twice and he saved 78% of the break points that he conceded.
| O Connell | |||
| R1 Sinclair |
Total | ||
|---|---|---|---|
| Score | 6-77 7-610 7-63 | ||
| Tot Set | 3 | 3 | |
| Tot Games | 39 | 39 | |
| pts | 129-129 | 129-129 | |
| Total points | 258 | 258 | |
| Winners | 57 | 57 | |
| %Winners | 44% | 44% | |
| SERVE | |||
| Aces | 12 | 12 | |
| Double Faults | 4 | 4 | |
| 1st in | 77/133 | 77/133 | |
| % 1st in | 58% | 58% | |
| 1st pts | 57/77 | 57/77 | |
| % 1st pts | 74% | 74% | |
| 2nd pts | 34/56 | 34/56 | |
| % 2nd pts | 61% | 61% | |
| Breaks | |||
| Won | 1 | 1 | |
| Converted | 1/4 | 1/4 | |
| Converted % | 25% | 25% | |
| Conceded | 5 | 5 | |
| Saved | 4/5 | 4 | |
| Saved % | 80% | 80% | |
| Times Broken | 1 | 1 | |
| Zhukayev | |||
| R1 Sugita |
Total | ||
|---|---|---|---|
| Score | 4-6 6-4 6-4 | ||
| Tot Set | 3 | 3 | |
| Tot Games | 30 | 30 | |
| pts | 96-87 | 96-87 | |
| Total points | 183 | 183 | |
| Winners | 50 | 50 | |
| %Winners | 52% | 52% | |
| SERVE | |||
| Aces | 24 | 24 | |
| Double Faults | 3 | 3 | |
| 1st in | 66/99 | 66/99 | |
| % 1st in | 67% | 67% | |
| 1st pts | 50/66 | 50/66 | |
| % 1st pts | 76% | 76% | |
| 2nd pts | 15/33 | 15/33 | |
| % 2nd pts | 45% | 45% | |
| Breaks | |||
| Won | 3 | 3 | |
| Converted | 3/6 | 3/6 | |
| Converted % | 50% | 50% | |
| Conceded | 9 | 9 | |
| Saved | 7/9 | 7 | |
| Saved % | 78% | 78% | |
| Times Broken | 2 | 2 | |
Head 2 Head
LLLLLWWLWW
LWWLWWLLWW Tennis Scores in Kobe Challenger
- Nino SerdarusicSerdarusic – Damir DzumhurDzumhur (4-6 6-1 6-3) – Stats, scores, rankings
- Frederico Ferreira SilvaFerreira Silva – Rinky HijikataHijikata (6-4 6-2) – Stats, scores, rankings
- John MillmanJohn – Shintaro ImaiShintaro (6-1 6-4) – See score progression
Upcoming matches in the draw
- Ramkumar RamanathanRamanathan – Jason JungJung (1-1) – H2H and prediction
- Christopher O ConnellO Connell – Beibit ZhukayevZhukayev (0-0) – H2H and prediction
- Nino SerdarusicSerdarusic – John MillmanMillman (0-0) – H2H and prediction
- Zdenek KolarKolar – Marc PolmansPolmans (1-0) – H2H and prediction
- Sho ShimabukuroShimabukuro – Yosuke WatanukiWatanuki (1-2) – H2H and prediction
- Shinji HazawaHazawa – Naoki NakagawaNakagawa (0-1) – H2H and prediction
