[UPDATED QF]. Prediction, H2H of Christopher O Connell’s draw vs Brooksby, Nakashima, Evans to win the San Diego

San Diego draw preview with H2H - Christopher O Connell may need to beat Jenson Brooksby, Brandon Nakashima, Daniel Evans to conquer the title in the San Diego Open.

Christopher O Connell Stats info

Christopher O Connell is 3 wins away to conquer the title in San Diego. O Connell has defeated Jason Murray Kubler 4-6 6-3 0-0 ret. and Jeff Wolf 6-3 7-5 to reach the quarter where he will face Jenson Brooksby.

Draw prediction with head to head records

This is Christopher O Connell’s projected draw and the likely opponents in San Diego Open. Christopher has no record against the presumable opponents.

R1 – Jason Murray Kubler (99) – 4-6 6-3 0-0 ret.
R2 – Jeff Wolf (73) – 6-3 7-5
1/4 – Jenson Brooksby (50) – H2H 0-0
1/2 – Brandon Nakashima (69) – H2H 0-0
or Daniel Elahi Galan (75) – H2H 0-0
Fin – Daniel Evans (25) – H2H 0-0
or Marcos Giron (58) – H2H 1-0
O Connell
Latest Updated
Draw

See Updated Draw

1/4 – Jenson Brooksby’s rankings and performance.

Head to head record 0-0

27 - 23win/loss in 2024

Rank
48
High
33
Year Total Hard Clay I.hard Grass Carpet
2022 27-23 16-10 2-4 6-5 3-4 0-0
2021 49-12 26-8 8-1 11-2 4-1 0-0
2020 0-0 0-0 0-0 0-0 0-0 0-0
2019 30-11 28-9 2-2 0-0 0-0 0-0
2018 25-15 12-11 4-1 9-3 0-0 0-0
2017 14-12 8-7 6-4 0-1 0-0 0-0
2016 4-6 4-5 0-0 0-1 0-0 0-0

Jenson Brooksby has a 25-18 win-loss record in 2022, 14-8 on hard. As for the previous 2 years, Jenson has a 40-16 record on hard. The American won 5 of his last 10 matches.

Brooksby’s most significant result of the current season was getting to the final Dallas and Atlanta.

Last year in San Diego Open Jenson didn’t take part in the competition.

H2H Christopher O Connell vs. Jenson Brooksby

There is no head to head record between Christopher O Connell and Jenson Brooksby since this would be the first time that they will fight against each other in the main tour.

1/2 – Brandon Nakashima’s rankings and performance.

Head to head record 0-0

41 - 26win/loss in 2024

Rank
47
High
35
Year Total Hard Clay I.hard Grass Carpet
2022 41-26 17-13 5-5 9-4 10-4 0-0
2021 45-25 17-10 4-7 20-5 4-3 0-0
2020 28-14 19-6 4-4 5-3 0-0 0-1
2019 18-9 11-6 0-0 7-3 0-0 0-0
2018 9-5 9-5 0-0 0-0 0-0 0-0
2017 1-1 1-1 0-0 0-0 0-0 0-0
2016 2-2 1-1 0-0 1-1 0-0 0-0

Brandon Nakashima has a 29-22 record in 2022, 13-12 on hard. Regarding the previous 7 years, the American has a 71-41 record on hard (Click here to see full career record). Nakashima won 6 of his last 10 matches.

Last year in San Diego Open Nakashima was overcome by Andrey Rublev in the 2nd round 6-2 6-1.

H2H Christopher O Connell vs. Brandon Nakashima

There is no head to head record between Christopher O Connell and Brandon Nakashima since this would be the first time that they will square off in the main tour.

On the other hand, Christopher O Connell could face Daniel Elahi Galan. Their H2H record is 0-0.

Final – Daniel Evans’s rankings and performance.

Head to head record 0-0

35 - 27win/loss in 2024

Rank
27
High
21
Year Total Hard Clay I.hard Grass Carpet
2022 35-27 19-13 4-7 6-4 6-3 0-0
2021 27-24 12-11 6-6 3-4 6-3 0-0
2020 19-14 11-6 0-3 8-5 0-0 0-0
2019 55-30 31-17 3-4 7-6 14-3 0-0
2018 31-13 13-7 0-0 7-2 11-4 0-0
2017 15-13 9-5 3-6 1-1 2-1 0-0
2016 39-22 17-10 0-0 12-7 5-5 5-0
2015 51-17 24-5 0-0 10-7 14-4 3-1

Daniel Evans has a 28-21 record in 2022, 17-10 on hard. In the last 16 years, the Brit has a 231-122 record on hard (Click here to see full career record). Daniel won 6 of his last 10 matches.

The Brit’s best achievement of the year was reaching the final the Nottingham Challenger.

Last year in San Diego Open the Brit surrendered to Cameron Norrie in the 2nd round 7-6(3) 6-3.

H2H Christopher O Connell vs. Daniel Evans

There is no head to head record between Christopher O Connell and Daniel Evans since this would be the first time that they will face off in the main tour.

However, Christopher O Connell may compete against Marcos Giron. Their H2H record is 1-0 for Christopher O Connell.